Question

A bag contains Rs. 1, Rs. 2 and Rs. 5 coins in the ratio 5: 9: 4 amounting to Rs. 129 find the number of coins of each type .

Answer 1

Let,
Coins of denominations Rs. 1= 5x
Coins of denominations Rs. 2= 9x
Coins of denominations Rs. 5= 4x
So,
Amount of Rs. 1= Rs. 5x*1
= Rs. 5x
Amount of Rs. 2= Rs. 9x*2
=Rs. 18x
Amount of Rs. 5= Rs. 4x*5
= Rs. 20x
A/q,
Amount of Rs. 1+Amount of Rs. 2+Amount of Rs. 5=129
5x+18x+20x=129
43x=129
x=129/43
x=3
Now,
Coins of denominations Rs. 1= 5x= 5*3=15

Coins of denominations Rs. 2= 9x=9*3=27

Coins of denominations Rs. 5= 4x=4*3=12

Answer 2

Answer:

1 rupee = 5x*1=5x

2 rupee = 9x*2=18x

5 rupee = 4x*5=20x

43x=129

x = 126/43=3

5*3=15 coins.

9*3=27coins.

4*3=12 coins.