Question

A bag contains rs 103 in the form of rupees fifty paise and ten paise coin in the ratio 3:4:20 find the no of 10 paise coins

Answer 1

Appropriate Question:

A bag contains Rs 103 in the form of 1 rupees, 50 paise and 10 paise coin in the ratio 3:4:20.Find the no. of 10 paise coins?

Given:

• A bag contains Rs 103 in the form of 1 rupees, fifty paise and ten paise coin in the ratio 3:4:20.

To find:

• The no. of 10 paise coins

Solution:

• Let us assume that 1 rupee, 50paise, 10paise coins be 3a, 4a and 5a respectively.

Then,

$\sf{3a+4a\times\frac{50}{100} + 20a \times \frac{10}{100} = 103 }$

$\sf \rightsquigarrow{ \: 3a + 4a \times \frac{1}{2} +20a \times \frac{10}{100} = 103}$

$\sf \rightsquigarrow{ \: 3a + 2a +20a \times \frac{1}{10} = 103}$

$\sf \rightsquigarrow{ \: 3a + 2a+2a = 103}$

$\sf \rightsquigarrow{ \: 5a + 2a = 103}$

$\sf \rightsquigarrow{ \: 7a = 103}$

$\sf \rightsquigarrow{ \: a= \frac{103}{7} = 14.71 } \\</p><p>$

$\sf \therefore \: {No.\: of \: 10 \: paise} \: coin = 20 \times 14.71 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \bf{294.2}$

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