Math, asked by sagarboruah1990, 10 months ago

a bag contains rs 112 in the form of 1 rupees, 50 paisa and 10 paisa coin in the ratio 3:8:10, what is the number of 50 paise coin? ​

Answers

Answered by soriful78
0

Step-by-step explanation:

50 \times 110

this is the answer.

Answered by franktheruler
0

Question:

a bag contains rs 120 in the form of 1 rupees, 50 paisa and 10 paisa coin in the ratio 3:8:10, what is the number of 50 paise coin? ​

[ note: Rs 112 is changed with Rs 120 because the total number of 50 paise coin can not be in float number. It should be a number which is divisible by 12. ]

Answer:

The total number of 50 paise coin = 80

Step-by-step explanation:

Let, required number of coins are 3x, 8x, 10x.

Bag contains rs 120

So, total Rs = 120

And we know that 50 paisa = 50/100 Rs, 10 paisa = 10/100 Rs

According to the question,

(3x * 1) + (8x * 50/100) + (10x * 50/100) = 120

⇒ 3x + 4x + 5x = 120

⇒ 12x = 120

⇒ x = 10

So, the total number of 50 paise coin = 10 * 8​ = 80

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