a bag contains rs. 121 in the form of 1 rupee, 50 paise and 25 paise coins in the ratio 1 : 2 : 3. find the number of each type of coins(1rs,50p,20p respectively)
Answers
1 rupee = 1x X 1 = 1x
50 paise (0.5 rupee) = 2x X 0.5 = 1x
25 paise ( 0.25rupee) = 3x X 0.25 = 0.75x
Total money = 121
1x + 1x + 0.75x = 121
2.75x = 121
x = 121/2.75 = 44
1rupee coin = 1x = 44
50 paise coin = 2x = 88
25paise coin = 3x = 132
Answer:
No. of coins of Rs.1 = 44
No. of coins of 50p = 88
No. of coins of 25p = 132
Step-by-step explanation:
Total amount in the bag = Rs. 121
It is given that the bag has Rs. 1 , 50p , 25p in the ratio 1 : 2 : 3
Let the multiplying factor be 'x'
Therefore, the amount made up Rs. 1 coins = x * 1 = x
The amount made up 50p coins = 2x * 0.50 = x
The amount made up 25p coins = 3x * 0.25 = 0.75 x
=> x + x + 0.75x = 121
=> 2.75 x = 121
=> x = 121/ 2.75
=> x = 44
Therefore, no. of coins of Rs.1 = 44
No. of coins of 50p = 2*44 = 88
No. of coins of 25p = 3*44 = 132