Question

A bag contains rs 187 in the form of 1 rs , 50 paise and 10 paise coins in the ratio of 3:4:5 . Find the number of each type of coins ?

Answer 1

Answer: There are 102 coins of Re. 1, 136 coins of 50 paise and 170 coins of 10 paise.

Step-by-step explanation:

Since we have given that

The ratio of Re. 1 , 50 paise and 10 paise coins are in the ratio is 3:4:5.

So, Let the number of Re. 1 note be 3x

Let the number of 50 paise coins be 4x

Let the number of 10 paise coins be 5x

Amount from Re. 1 note is given by

$3x\times 1=3x$

Amount from 50 paise is given by

$\frac{50}{100}\times 4x\\\\=\frac{4x}{2}=2x$

Amount from 10 paise is given by

$\frac{10}{100}\times 5x\\\\=0.1\times 5x\\\\=0.5x$

So, Total amount is given as Rs. 187.

According to question, we have

$3x+2x+0.5x=187\\\\5.5x=-187\\\\x=\frac{187}{5.5}\\\\x=34$

Hence, Number of Re.1 note is 3x = 3× 34 =102

Number of 50 paise coins is 4x =4×34=136

Number of 10 paise coins is 5x = 5×34 = 170

Answer 2

Answer:

please mark me as brainlist