Math, asked by madhu856, 7 months ago


A bag contains Rs. 187 in the form of 1 rupee, 50 paisa and 10 paisa coins in the ratio 3:4:5.
Find the number of each type of coins:​

Answers

Answered by Ray2006
5

Answer:

Rs.1 → 102

50p → 136

10p → 170

Step-by-step explanation:

Let us assume, the number of Rs 1, 50 paise and 10 paise are 3x, 4x and 5x respectively.

3x number of Rs 1 = Rs 3x

4x number of 50 paise = Rs. 2x [50 paise = Rs. 0.5 ]

5x number of 10 paise = Rs. 0.5x [ 10 paise = Rs 0.1]

According to the problem, 3x + 2x + 0.5x = 187

or, 5.5x = 187

x = 187/5.5 = 34

So, number of Rs 1 is = 3 * 34 = 102

number of 50 paise is = 4 * 34 = 136

number of 10 paise is = 5 * 34 = 170

Answered by ecraaclingom
1

Answer:

Step-by-step explanation:

Rs.1 → 102

50p → 136

10p → 170

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