Question

A bag contains Rs. 372 in the form of 50 paise, 25 paise and 20 paise coins in the ratio
4 : 5 : 7. Find the number of each type of coin

Answer 1

Answer:29,50,30

Step-by-step explanation:

In a bag 50 paise coins,25 paise coins, and 20 coins whose values are in the ratio of 4:5:7 the total values of coins are 372

We need to find the total number of coins.

Solution

Let us assume that

Number of 25p coins = 5x

Number of 50p coins = 4x

Number of 20p coins = 7x

As per the given condition

5x + 4x + 7x =372

16x = 372

x = $\frac{372}{16}$

x = $\frac{372}{16}$ = 23.25

Hence,

Amount of 25p coin = 23.25 × 5 × 25 = 2,906.25 paisa = Rs. 29.0625

Amount of 50p coin = 23.25 × 4 × 50 = 4,650 paisa = Rs. 46.50

Amount of 20p coin = 23.25 × 7 × 20 =3,255 paisa Rs. 33.55

If we will do round up answer is 29,50,30

Answer 2

Answer:

There are 320 coins of 50 paisa, 400 coins of 25 paisa and 560 coins of 20 paisa.

Step-by-step explanation:

Let,

The number of 50 paise coin = 4x

The number of 25 paise coin = 5x

The number of 20 paise coin = 7x

Total amount = Rs. 372

__________________________

★ Value of coins =

• 50 paise coin = 2x

⇒ 4x (50/100) = 4x (0.5)

• 25 paise coin = 1.25x

⇒ 5x (25/100) = 5x (0.25)

• 20 paise coin = 1.4x

⇒ 7x (20/100) = 7x (0.2)

__________________________

★ According to the Question :

⇒ 2x + 1.25x + 1.4x = 372

⇒ 4.65x = 372

⇒ x = 372 / 4.65

⇒ x = 80

__________________________

The number of 50 paise coin = 4x

⇒ 4 (80)

⇒ 320

The number of 50 paise coin = 320

The number of 25 paise coin = 5x

⇒ 5 (80)

⇒ 400

The number of 25 paise coin = 400

The number of 20 paise coin = 7x

⇒ 7 (80)

⇒ 560

The number of 20 paise coin = 560

Therefore, there are 320 coins of 50 paisa, 400 coins of 25 paisa and 560 coins of 20 paisa.