Question

A bag contains rs 510 in form of 50 paise 20 paise 25 paise in ration of 2:3:4

Answer 1

Answer:

LET COINS BE. 2x , 3x , 4x

50paise = 50/100 = rs. 1/2

25paise = 25/100 = rs. 1/4

20paise = 20/100 = rs. 1/5

1/2*2x + 1/4*3x + 1/5*4x = 510

x + 3/4x + 4/5x =510

(20x +15x + 16x)/20 = 510

51x/20 = 510

x = 510*20/51

x = 200

hence ,

coins of 50 paise will be 2x = 2*200 = 400

coins of 25 paise will be 3x = 3*200 = 600

coins of 20 paise will be 4x= 4*200 = 800

Answer 2

Given that : A bag contains Rs. 510 in form of 50 paise 20 paise and 25 paise in the ratio of 2:3:4

Let, 50 paise = 2x , 20 paise = 3x and 25 paise = 4x

Now convert paise into rupees :

As we know that : 1 rupee = 100 paise

then, 50 paise = 50/100 = 1/2 rupees

20 paise = 1/5 rupees and

25 paise = 1/4 rupees

Now, according to the question :

(1/2×2x)+(1/4×3x)+(1/5×4x) = 510

=> x+3x/4+4x/5= 510

=> 51x/20 = 510

=> x = 200

So, 50 paise = 2x = 2×200 = 400

20 paise = 3x = 3×200 = 600

25 paise = 4x = 4×200 = 800