Question

a bag contains rs 600 in the form of one rupee, 50paise and 25 pause coins in the ratio of 3:4:12 . find the total number of 25 pause coins in the bag

Answer 1

Rs 600=600*100 p= 60000 p
Let the no. of Rs 1, 50 p and 25 p coins be 3x, 4x and 12x
Therefore,
Money in Rs 1 (100 p)= 3x*100=300x
Money in 50 p= 4x*50= 200x
Money in 25 p=12x*25= 300x
Therefore-
300x+200x+300x= 60000
or 800x= 60000
or x= 60000/800= 75
Thus,
No. of Rs 1 coins= 3*75= 225
No. of 50 p coins= 4*75= 300
No. of 25 p coins= 12*75= 900
Hope this helps! 

Answer 2

Rs 600=600*100 p= 60000 p

Let the no. of Rs 1, 50 p and 25 p coins be 3x, 4x and 12x

Therefore,

Money in Rs 1 (100 p)= 3x*100=300x

Money in 50 p= 4x*50= 200x

Money in 25 p=12x*25= 300x

Therefore-

300x+200x+300x= 60000

or 800x= 60000

or x= 60000/800= 75

Thus,

No. of Rs 1 coins= 3*75= 225

No. of 50 p coins= 4*75= 300

No. of 25 p coins= 12*75= 900

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