Question

A bag contains rs155 in the form of 1-rupee, 50 - paise and 10-paise coins in the ratio of 3:5:7. find the number of each type of coins?

Answer 1

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Answer 2

Answer:

There are 75,125 and 175 coins of 1-rupee, 50 - paise and 10-paise respectively.

Step-by-step explanation:

A bag contains Rs 155 in the form of 1-rupee, 50 - paise and 10-paise coins in the ratio of 3:5:7.

Let the ratio be x

So, No. of 1-rupee coins = 3x

Value of 3x 1-rupee coins = 3x

No. of 50-paisa coins = 5x

Value of 5x 50-paisa coins = 250x paisa = Rs.2.5x

No. of 10-paisa coins = 7x

Value of 7x 10-paisa coins = 70x paisa = Rs.0.7x

Now we are given that the total sum is rs.155

So,$3x+2.5x+0.7x=155$

$6.2x=155$

$x=\frac{155}{6.2}$

$x=25$

No. of 1-rupee coins = 3x = 3*25 =75

No. of 50-paisa coins =5x= 5*25 = 125

No. of 10-paisa coins = 7x = 7*25 = 175

Hence There are 75,125 and 175 coins of 1-rupee, 50 - paise and 10-paise respectively.