Question

'a bag contains RS155 in the form of 1RS,50 paise,10 paise coins in the ratio 3:5:7. find the no.of of each type of coins'

Answer 1

(3×1×x)+(5×0.5×x)+(7×0.1×x)=155 3x+2.5x+0.7x=155 6.2x=155 X =155÷6.2=25 3×25×1Rs =75 1Rupee 5×25×50paise= 125 50paise 7×25 ×10paise = 175 10 paise 75+ 62.5+17.5= 155

Answer 2

there are (3*1x)+(5*.5x)+(7*.1x)=155
3x+2.5x+.7x=155
6.2x=155
x=25
therefore 1rs= 3x=75
50paise=125
10paise=175