Question

a bag contains Rs396 in terms of 50 paise,2rupees and 5 rupees coins in the ratio 4:3:2. find the number of each type of coins.

Answer 1

50 PAISE = RS. 0.50
NO. OF RS. 0.50 COIN = 4x
COST OF RS. 0.50 COIN = 4x×RS. 0.50
= RS. 2x
NO. OF RS. 2 COIN = 3x
COST OF RS. 2 COIN = RS. 2×3x
= RS. 6x
NO. OF RS. 5 COIN = 2x
COST OF RS. 5 COIN = RS. 5×2x
= RS. 10x
A/Q,
2x+6x+10x=396
=> 18x=396
=> x=396/18
=>. x=22

therefore, no. of RS. 5 coin = 2x = 2×22 = 44
no. of RS. 2 coin = 3x = 3×22 = 66
no. of RS. 0.50 coin = 4x = 4×22 = 88

Answer 2

A purse contains ₹1800 in term of 50 paisa ,2 rupees and 5 rupees coins in the ratio 2:3:4.Find the number of each type of coins.