A bag contains Rs500 in notes of denomination of Rs 10 and Rs 50. If the total number of notes is 30, then the number of Rs 10 notes is
Answers
Answer:
Let us assume the number of 5 rupees note be 'x'. Then the number of 10 rupees note will be '90-x' (Total number of notes=90)
The total amount is 500. So according to the question:
5x+10(90-x)=500
5x+900–10x=500
-5x=500–900
-5x=—400
X=—400/—5 (Since, — and — = +)
X=400/5
X=80
Hence, according to our solution:—
Number of 5 rupees note=X that is 80
And number of 10 rupees note=(90-x) that is (90–80)=10
Therefore, there are 80 five rupees note and 10 ten rupees note..
Step-by-step explanation:
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Answer:
TO FIND :
A bag contains Rs500 in notes of denomination of Rs 10 and Rs 50. If the total number of notes is 30, then the number of Rs 10 notes .
Let the number of 5 rupee notes be x,then
Let the number of 5 rupee notes be x,thenThe number of 10 rupee notes =90−x
Let the number of 5 rupee notes be x,thenThe number of 10 rupee notes =90−xThen ,according to the question
Let the number of 5 rupee notes be x,thenThe number of 10 rupee notes =90−xThen ,according to the question5x+10(90−x)=500
Let the number of 5 rupee notes be x,thenThe number of 10 rupee notes =90−xThen ,according to the question5x+10(90−x)=5005x+900−10x=500
Let the number of 5 rupee notes be x,thenThe number of 10 rupee notes =90−xThen ,according to the question5x+10(90−x)=5005x+900−10x=5005x=400
Let the number of 5 rupee notes be x,thenThe number of 10 rupee notes =90−xThen ,according to the question5x+10(90−x)=5005x+900−10x=5005x=400x=80
Let the number of 5 rupee notes be x,thenThe number of 10 rupee notes =90−xThen ,according to the question5x+10(90−x)=5005x+900−10x=5005x=400x=80There are 80 notes of Rs.5 and 10 notes of Rs.10.