Question

A bag contains Rs750 in the form of rupee, 50P and 25P coins in the ratio 5:8:4. Find the

number of coins of each type.​

Answer 1

Answer:

Total amount in the bag=Rs 750

Let the number of rupee be 5x, number of 50 paisa coin be 8x and number of 25 paisa coin be 4x

According to the question

5x(1)+8x(0.5)+4x(0.25)=50

5x+4x+x=750

10x=750

x=75

Therefore,

Number of coin of rupee=5×75=375

Number of coin of 50 paisa =8×75=600

Number of coin of 25 paisa=4×75=300

hope this helps u..

Answer 2

$\huge{\underline{\underline {\mathtt{\purple{Hola\:}\pink{Mate}}}}}$

$\Large\bold\red{Question}$

A bag contains Rs750 in the form of rupee, 50 P and 25 P coins in the ratio 5:8:4. Find the number of coins of each type.

$\Large\bold\green{Given}$

◇ Total amount in the bag = Rs 750

◇ Ratios = 5:8:4

$\Large\bold\green{To\:Find}$

◇ The number of coins of each type.

$\Large\bold\red{Solution}$

Let the number of rupee be 5x

Let the number of 50 paisa coin be 8x

Let the number of 25 paisa coin be 4x

From the question

5x (1) + 8x (0.5) + 4 x (0.25) = 50

5x + 4x + x = 750

10x = 750

$x = \frac{750}{10} = 75$

$\Large\fbox\blue{⇒ x \: = \:75}$

Therefore,

$\small\bold\orange{No. \:of\:coin\:as\:rupee = 5 × 75 = 375}$

$\small\bold\orange{No.\:of\:coin\:as\:50\:paisa = 8 × 75 = 600}$

$\small\bold\orange{No.\:of\:coin\:as\:25\:paisa = 4 × 75 = 300}$

$\Large\fbox\red{Mark \: As \:Brainliest}$