A bag contains rupees 300 in the form of 1-ruppees,50-paise and 25 paise coins in the ratio 5:8:4.Find the number of coins of each type.
Answers
Answered by
1
Answer:
No. of Coins: 5x,8xand 4xof
Rel/-, Rel/2 and Re1/4
5Xx1.+8X x 1/2+4Xx 1/4 = 300
5x+4x + x=300
I0x=300
x = 30
5x=150,
8x=240
4x=120
I rupee = 150 Nos
50 ps=240 Nos
25 ps=120 Nos
Answered by
2
Step-by-step explanation:
Let the common number be = m
Then 5 = 5m
8 = 8m
4 = 4m
=> (1 × 5m) + (50p × 8m) + (25p × 4m) = 300
=> (1 × 5m) + (0.50 × 8m) + (0.25 × 4m) =300
=> 5m + 4m + 1m = 300
=> 10m = 300
=> m = 300/10
=> m = 30,,
So, no of 1 rupee coins => 5m = 5×30 = 150.
no of 50 paise coins => 8m = 8 × 30 = 240.
no of 25 paise coins => 4m = 4 × 30 = 120.
1 × 150 = 150 rupees
0.50 × 240 = 120 rupees
0.25 × 120 = 30 rupees
150 + 120 + 30 = 300 rupees
Therefore, there are 150 no of 1 rupee coins, 240 no of 50 paise coins and 120 no of 25 paise coins.
Similar questions