a bag contains rupees 396 in term of 50 paise, 2 rupees and 5 rupees coins in the ratio 4 : 3 : 2. find the number of each type of coins.
Answers
Answered by
24
Explanation.
Coins of 50 paise = 4x
Rupees = 4x*50=200x
= 100 paise=1rupees
= 200x paise =2x Rupees
Coins of 2 rupees = 3x
Rupees = 3x*2=6x
Coins of 5 rupees = 2x
Rupees = 5*2x=10x
Total money =396 Rs
2x + 6x + 10x = 396
18x = 396
x=396/18
x=22
Answer.
50paise coins = 4x
=4*22
= 88
2 rupee coins =3x
= 3*22
= 66
5 rupees coins =2x
= 2*22
= 44.
Verification.
No. of 50 paise coin = 88
amount. = 88*50=4400 paise
= 44 rupees
No. of 2 rupees coins =66
amount = 66*2
= 132 rupees
No.of 5 rupees coins =44
amount. = 44*5
=220 rupees
Total = 44+132+220
=396.
Similar questions