Math, asked by Yashugehlot1417, 9 months ago

a bag contains rupees 396 in term of 50 paise, 2 rupees and 5 rupees coins in the ratio 4 : 3 : 2. find the number of each type of coins.

Answers

Answered by vandna469
24

Explanation.

Coins of 50 paise = 4x

Rupees = 4x*50=200x

= 100 paise=1rupees

= 200x paise =2x Rupees

Coins of 2 rupees = 3x

Rupees = 3x*2=6x

Coins of 5 rupees = 2x

Rupees = 5*2x=10x

Total money =396 Rs

2x + 6x + 10x = 396

18x = 396

x=396/18

x=22

Answer.

50paise coins = 4x

=4*22

= 88

2 rupee coins =3x

= 3*22

= 66

5 rupees coins =2x

= 2*22

= 44.

Verification.

No. of 50 paise coin = 88

amount. = 88*50=4400 paise

= 44 rupees

No. of 2 rupees coins =66

amount = 66*2

= 132 rupees

No.of 5 rupees coins =44

amount. = 44*5

=220 rupees

Total = 44+132+220

=396.

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