a bag contains rupees,50 paise,and 25 paise coins in the proportion 5:6:8.if the total amount is 210,find the number of coins of each kind
Answers
Answered by
1
let the no. if one rs coin = 5x
no. of 1/2 =6x
no. of 1/4 = 8x
5x+1/2*8x+1/4*8x=210
x=21
no of 1 rs coin = 5*21=105
no of 25 paisa coin =6*21=126
no. of 50 paisa coin = 8*21=168. @
no. of 1/2 =6x
no. of 1/4 = 8x
5x+1/2*8x+1/4*8x=210
x=21
no of 1 rs coin = 5*21=105
no of 25 paisa coin =6*21=126
no. of 50 paisa coin = 8*21=168. @
Similar questions