Question

A bag contains rupees 50p, 25p and 10p in the proportion 1:3:5:7. If the total amount is 22.25 find
the no. of coins of each kind.​

Answer 1

Answer:

The number of coins of each kind are 5, 15, 25, 35 respectively.

Step-by-step explanation:

The bag contains 1 rupee, 50 paise, 25 paise, and 10 paise in 1:3:5:7 ratio.

Let us assume that in the bag there are x numbers of 1 rupee, 3x numbers of 50 paise, 5x numbers of 25 paise and 7x numbers of 10 paise.

Now, given that there are 22.25 rupees in total in the bag.  

So, we can write, x+ (50/100)3x+(25/100)5x+(10/100)7x = 22.25

⇒x+(3/2)x+(5/4)x+(7/10)x =22.25

⇒ x+1.5x+1.25x+0.7x = 22.25

⇒4.45x = 22.25

⇒x= 5

Therefore, there are 5 numbers of 1 rupee coin, (5*3)=15 numbers of 50 paise coin, (5*5)=25 numbers of 25 paise coin, and (5*7)=35 numbers of 10 paise coin.

Hence, the number of coins of each kind is 5, 15, 25, 35 respectively.  

(Answer)