A bag contains rupees155 in the form of 1 rupee, 50 paise, 10 paise coins in the ratio of 3
: 5 : 7. Find the number of each type of coin.
Answers
Answer:
There are 75,125 and 175 coins of 1-rupee, 50 - paise and 10-paise respectively.
Explanation:
A bag contains Rs 155 in the form of 1-rupee, 50 - paise and 10-paise coins in the ratio of 3:5:7.
Let the ratio be x
So, No. of 1-rupee coins = 3x
Value of 3x 1-rupee coins = 3x
No. of 50-paisa coins = 5x
Value of 5x 50-paisa coins = 250x paisa = Rs.2.5x
No. of 10-paisa coins = 7x
Value of 7x 10-paisa coins = 70x paisa = Rs.0.7x
Now we are given that the total sum is rs.155
So,
3X+2.5x+0.7x = 155
6.2x = 155
x = 155/6.2
x = 25
No. of 1-rupee coins = 3x = 3*25 =75
No. of 50-paisa coins =5x= 5*25 = 125
No. of 10-paisa coins = 7x = 7*25 = 175
Hence There are 75,125 and 175 coins of 1-rupee, 50 - paise and 10-paise respectively.
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