A bag contains rupi rupi 396 in term of 50 paise 2 rupees and 5 rupees coins in the ratio of 4:3:2 find number of each types of coins
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50 PAISE = RS. 0.50
NO. OF RS. 0.50 COIN = 4x
COST OF RS. 0.50 COIN = 4x×RS. 0.50
= RS. 2x
NO. OF RS. 2 COIN = 3x
COST OF RS. 2 COIN = RS. 2×3x
= RS. 6x
NO. OF RS. 5 COIN = 2x
COST OF RS. 5 COIN = RS. 5×2x
= RS. 10x
A/Q,
2x+6x+10x=396
=> 18x=396
=> x=396/18
=>. x=22
therefore, no. of RS. 5 coin = 2x = 2×22 = 44
no. of RS. 2 coin = 3x = 3×22 = 66
no. of RS. 0.50 coin = 4x = 4×22 = 88
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1
50 paisa=4×44=176
2 rupees=3×44=132
5 rupees=2×44=88
2 rupees=3×44=132
5 rupees=2×44=88
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