A bag contains slips bearing numbers from 1-89.A slip is drawn at random from the bag. Find the probability that the slip drawn has: (I) a number written on it such that sum of it's digits is 11. (ii) a number greater than 63 written on it.
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1) There are 7 2-digit numbers whose sum of the digits is 11.They are 29,38,47,56,65,74,83.
Therefore the probability=favourable outcomes/total outcomes.
=7/89
2)The numbers greater than 63=89-63
=26
Therefore, probability=26/89
Hope this helps you.
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