Question

a bag contains slips numbered from 66to 93 .a slip is taken at a random what is the probability that the slip taken bears a multiple of 11​

Answer 1

Answer:

Step-by-step explanation:

Total slip = 28

Slip containing multiple of 11 = 3

So, probability = 3/28

Answer 2

$A\:bag \:contains \:slips \: numbered \:from \\66 \:to \:93 .$

$Number \:of \: total \: possible \\outcomes =28\: --(1)$

$Favourable\: outcomes = multiple \:of \:11 \: from \: 66 \:to \:93 \\=\{ 66, 77,88 \}$

$Number \: of \: favourable \: outcomes = 3\:--(2)$

$Probability \:of \: the \:slip \:taken \:bears \\a \:multiple \:of \:11 = \frac{(2)}{(1)} \\= \frac{3}{28}\\= 0.107$

Therefore.,

$\red { Probability } \green {= \frac{3}{28}= 0.107}$

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