Question

A bag contains some balls of which x are white ,2x are black and 3x are red.a ball is selected at random find the probability that it is 1.not red 2.white

Answer 1

Answer:

total balls=2x+3x+x=6x

not red=x+2x=3x

probability of non red ball=3x/6x=1/2

total balls=6x

white balls=x

probability=x/6x=1/6

hope it helps..

if yes mark as brainliest

Answer 2

Answer: 1. $\dfrac{1}{2}$

2.$\dfrac{1}{6}$

Step-by-step explanation: Given that

Number of white balls =x  

Number of black balls = 2x

Number of red balls= 3x

Therefore total number of balls will be= $x+2x+3x$= $6x$

Probability of any outcome is given by

P(Event)=  $\dfrac{\text{Number of favourable outcomes}}{\text{Total outcomes}}$

1. Number of Balls which are not red = Total balls-Red balls= $6x-3x=3x$        

P(not red)  =    $\dfrac{3x}{6x}$    

                 =    $\dfrac{1}{2}$

2.Number of white balls =x

P(white)    =    $\dfrac{x}{6x}$    

                 =    $\dfrac{1}{6}$