A bag contains some balls of which x are white , 2x are black and 3x are red. A ball is selected at random. Find the probability that it is
(i) not red
(ii) white
PLEASE HELP ME GUYS... I NEED STEP-BY-STEP EXPLANATION....
Answers
Step-by-step explanation:
total no of ball is x+2x+3x is 6x
total no of ball not red is 3x
probability is 3x/6x=1/2
probability =x/6x=1/6
Answer:
Their are 50 percent chance of get ball which is not red
Their are 16.67 percent changes of getting white ball
Step-by-step explanation:
Since we are given that
Number of white balls = x
Number of black balls = 2x
Number of red balls = 3x
Total number of balls = Sum of whits , reds and blacks
= x + 2x + 3x
= 6x
So
Total simple space = 6x
Number of balls which are not red = Total - red balls = 6x - 3x = 3x
So
The desire space = 3x
Thus
Probability of not getting red ball = desire space / total space = 3x / 6x = 1/2
Thus
Their are 50 percent chance of get ball which is not red
Now
Number of white balls = x
The desire space = x
Thus
Probability of getting white ball = desire space / total space = x / 6x = 1/6
And we know that
1/6 ≈ 16.67
Thus
Their are 16.67 percent changes of getting white ball