Question

A bag contains some cards which are numbered between 31 and96 are placed. If one card is drawn from the bag, find the probability that the number on card is:(i) a multiple of 3 (ii) a perfect square (iii) a number not more than 40.

Answer 1

Answer:

(1)21/65...

(2)8/65...

(3)40/65

Answer 2

(i) a multiple of 3 =  $\frac{1}{3}$    (ii) a perfect square =  $\frac{2}{33}$      (iii) a number not more than 40. =  $\frac{3}{22}$

Given:

A bag contains some cards which are numbered between 31 and 96 are placed.

One card is drawn from the bag.

To find:

Probability that the number on card is

(i) a multiple of 3.

(ii) a perfect square.

(iii) a number not more than 40.

Explanation:

Sample size n(s) = numbered between 31 and 96 = 96 -31+1 = 66

(i) a multiple of 3. Consider n(x) = (33,36,39 ......... 96) = 22

Probability = $\frac{22}{66}$ = $\frac{1}{3}$

(ii) a perfect square. Consider n(y) = (36 , 49 ,64 ,81 ) = 4

Probability = $\frac{4}{66}$ = $\frac{2}{33}$

(iii) a number not more than 40.

Consider n(z) = (31,32,33,34,35,36,37,38,39) = 9

Probability = $\frac{9}{66}$ = $\frac{3}{22}$

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