Question

A bag contains some cards which are numbered between 31 and 96 are placed. If one card is drawn from the bag, find the probability that the number on card is:
(i) a multiple of 3 (ii) a perfect square (iii) a number not more than 40.

Answer 1

Answer:

Step-by-step explanation:

Bag contain cards from 31 to 96

So  Total numbers are 96-31+1=66; +1 because 31 is also included

1) multiple of 3 in between 31 to 96 is ( 33 ,36,39 ,42,45,48,52,54,57,60,63,66,69,72,75,78,81,84,87,91,94)

So number of favourable event = 21

Hence the probability = 21/66 = 7/22

2) A perfect square is

( 36 , 49 , 64 ,81)

So probability = 4/66 =2/33

3)number not more than 40 is 31,32,33,34,35,36,37,38,39

So there are 9 numbers

hence the probability = 9/66 = 3/22

Answer 2

Answer:

There  are 96-31 + 1 = 66 cards

(i)  (96-33) / 3  + 1 = 22,  P( 22/66) = 1/3

(ii) 36, 49, 64,81,  P ( 4/66) = 2/33

(iii) P ( number <=40) = 10/66 = 5/33

Step-by-step explanation: