Question

A bag contains some coins of denomination 25 paisa, 50 paisa and rupee 1 , respectively. The number of 50paise coins is 5 times the number of rupee 1 coin and number of 25 paise coins is twice the number of 50 coins If the total amount of money in the bag is rupee 72 ,find the number of coins of each denomination present in the bag

Answer 1

Answer:

Total amount in the bag = Rs. 30=3000 paise

Let the number of 50 paise coins be x

Then the number of 25 paise coins =4x

Now, according to the question

25(4x)+50x=3000

100x+50x=3000

150x=3000

x=

150

3000

x=20

4x=80

Therefore, number of 50 paise coins =20

Number of 25 paise coins =80

Answer 2

Step-by-step explanation:

Given: one root of the equation 2x² + Px - 5 = 0 is - 5 and the quadratic equation p(x² + x) + k = 0 has equal roots.

To find: The value of k

solution : one root of the equation 2x² +

px - 5 = 0 is -5

so, 2(-5)² + p(-5) - 5 = 0

→ 2 × 25 - 5p - 5 = 0

⇒ 45 - 5p = 0

⇒p=9

now the quadratic equation p(x² + x) + k =

9(x² + x) + k = 0

→ 9x² + 9x + k = 0

Discriminant = (9)2 - 4(9)(k)= 0 [for equal roots ]

→ 81-36k = 0

⇒k = 81/36 = 9/4