a bag contains some coins of denomination 25 paise 50 paise and 1rs respectively the number of 50 paise coins is 5 times the number of 1rs coins and number of 25 paise coins is twice the number of 50 paise coins if the total amount of money in the bag 72 rs find the number of coins of each denominator present in the bag
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⇒3x+4x(0.,50)+5x(0.25)=500⇒3x+4x(0.,50)+5x(0.25)=500
⇒6.25x=500⇒x=80⇒6.25x=500⇒x=80
∴∴ The total number of 50-paise coins =4x=320=4x=320
But we can't be solved the question using statement (II).
Hence statement (I) alone is sufficient to answer the question.
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