A bag contains some one rupee 50-paise and 25-paise coins in the ratio 4:5:6 amounting to 160.Find the number of coin of each type
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1 rupee = 100 paise
let the no. of 100 p , 50p and 25 p coins be 4x ,5x and 6x respectively
total value of these coins = 4x ×100/100 + 5x ×50/100 + 6x × 25/100
= 4x + 5x/2 + 6x/4 =32x/4
but total value of coins = rupee 160
32x/4 = 160
x = 160×4/32 = 20
no.of 100 p= 4x = 4× 20=80
no. of 50p = 5x =5×20 = 100
no.of 25 p = 6x = 6×20 = 120
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let the no. of 100 p , 50p and 25 p coins be 4x ,5x and 6x respectively
total value of these coins = 4x ×100/100 + 5x ×50/100 + 6x × 25/100
= 4x + 5x/2 + 6x/4 =32x/4
but total value of coins = rupee 160
32x/4 = 160
x = 160×4/32 = 20
no.of 100 p= 4x = 4× 20=80
no. of 50p = 5x =5×20 = 100
no.of 25 p = 6x = 6×20 = 120
hope it helps
mark to brainlist if it help
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