A bag contains three green marbles, four blue marbles, and two orange marbles. If a marble is picked at random, then the probability that it is not an orange marble is
A. 1/4
B. 1/3
C. 4/9
D.7/9
Answers
GIVEN : A bag contains three green marbles, four blue marbles, and two orange marbles.
Solution :
We have , Number of green marbles = 3
Number of Blue marbles = 4
Number of orange marbles = 2
Total number of marbles in a bag = 3 + 4 + 2 = 9
Total number of outcomes = 9
Let E = Event of getting a marble which is not orange
Number of marbles which is not orange i.e green and blue marbles = (3 + 4) = 7
Number of outcome favourable to E = 7
Probability (E) = Number of favourable outcomes / Total number of outcomes
P(E) = 7/9
Hence, the probability of getting a marble which is not orange , P(E) = 7/9.
The correct option is (d) : 7/9
HOPE THIS ANSWER WILL HELP YOU……
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Step-by-step explanation:
green marbles = 3
Blue marbles = 4
orange marbles = 2
Total marbles = 3 + 4 + 2 = 9
Total number of outcomes = 9
P(E) = 7/9
Hence, the probability of getting a marble which is not orange , P(E) = 7/9.