Question

A bag contains three green marbles, four blue marbles, and two orange marbles, If a marble is picked at random, then the probability that it is not an orange marble is
(a)$\frac{1}{4}$
(b)$\frac{1}{3}$
(c)$\frac{4}{9}$
(d)$\frac{7}{9}$

Answer 1

SOLUTION :  

The correct option is (d) : 7/9

GIVEN : Number of green marbles = 3

Number of Blue marbles = 4

Number of orange marbles = 2

Total number of marbles in a bag = 3 + 4 + 2  = 9

Total number of outcomes = 9

Let E = Event  of getting a marble which is not orange

Number of marbles which is not orange i.e green and blue marbles = (3 + 4)= 7

Number of outcome favourable to E = 7

Probability (E) = Number of favourable outcomes / Total number of outcomes

P(E) = 7/9

Hence, the probability of getting a  marble which is not orange , P(E) = 7/9.

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Answer 2

correct answer is d) 7/9

total outcomes = 3+ 4 + 2
=9

not orange balls = 4+ 3 = 7

Probability =7/9

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