A bag contains total of Rs 2400 in the form of 25 ps, 50 ps and 1 Re coins. If the total amounts of each type of coins are in the ratio 3:4:5 find the total no of coins in the bag.
A. 2000coins
B. 4000 coins
C. 5500 coins
D. 5000 coins
Ans : D
Answers
Given : A bag contains total of Rs 2400 in the form of 25 ps, 50 ps and 1 Re coins. If the total amounts of each type of coins are in the ratio 3:4:5
To find : the total no of coins in the bag.
A. 2000coins
B. 4000 coins
C. 5500 coins
D. 5000 coins
Solution:
Total amounts of each type of coins are in the ratio 3:4:5
Let say amount are 3x , 4x and 5x
3x + 4x + 5x = 2400
=> 12x = 2400
=> x = 200
3x = 600 Rs coins of 25 ps = 600/(25/100) = 2400
4x = 800 Rs coins of 50 ps = 800/(60/100) = 1600
5x = 1000 Rs coins of 1 Rs = 1000/1 = 1000
Total Coins = 2400 + 1600 + 1000 = 5000
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Given:-
- a bag contains a total of Rs 2400 in the form of 25 Paise 50 paise and one rupee coins. The total amount of each type of coins are in the ratio 3:4:5
To Find:-
- The total number of coins in the bag
Solution:-
Let us assume the amounts as 3x, 4x and 5x
➻ 3x + 4x +5x = 2400
➻ 7x + 5x = 2400
➻ 12x = 2400
➻ x = 2400/12
➻ x = 200
Now,
- 3x = 3(200) = 600
Rs coins of 25 paise = 600 ÷ (25/100) = 2400
- 4x = 4(200) = 800
Rs coins of 50 paise = 800 ÷ (50/100) = 1600
- 5x = 5(200) = 1000
Rs coins of 1 rupee = 1000/1 = 1000
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∴ Total number of coins in the bag :-
2400 + 1600 + 1000
= 5000 Ans
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