Question

a bag contains x red balls and 12 black balls 3 red balls are added to the bag then ball is drawn at random if the probability of drawing a red ball is 1/3 find the number of red balls in bag intially​

Answer 1

Answer:

there are 3 red balls in the bag initally

Step-by-step explanation:

red balls are x

then 3 balls are added so it is x+3

black ball are 12

total balls are 12 +x+3= x+15

=>p(getting red balls) = 1/3

1/3= x+3/x+15

x=3

hope this will help you

Answer 2

The number of red balls in bag initially​ was 3.

Step-by-step explanation:

Consider the provided information.

Let the bag contains x red balls and 12 black balls 3 red balls are added to the bag.

Now the total number of balls in the bag are: x+12+3=x+15

Total number of red balls in the bag are: x+3

$Probability = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$

The probability of drawing a red ball is 1/3.

Substitute the respective values in the above formula.

$\frac{1}{3}= \frac{x+3}{x+15}$

$x+15=3(x+3)$

$x+15=3x+9$

$15-9=3x-x$

$6=2x$

$x=3$

Hence, the number of red balls in bag initially​ was 3.

#Learn more

Find the probablity​

https://brainly.in/question/8995906