A bag contains x white y red and z blue.a ball is drawn at the random, then the probability of drawing ablue ball is. z=X+y+z
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N(e)=z
N(s)=x+y+z
P(drawing a blue ball)=N(e)/N(s)
=z/x+y+z
N(s)=x+y+z
P(drawing a blue ball)=N(e)/N(s)
=z/x+y+z
Answered by
1
No. of blue balls = z
=:
N(e) = z
N(s) = x + y + z
P(drawing a blue ball) = N(e)
-------
N(s)
=. z
-------
x + y + z
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