A bag contest coins of 25paise and 50 paise in such a way that the total mamount is 120. If the number of 25 paise coins is thrice the number of 50 paise coins find their number (number of 25paise coins =288. Number of 50 paise coins =96).
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Let there are X one rupee's coin, Y 50 paise's coins and Z 25 paise's coins.
Now,
X +Y +Z = 220 ---------------- (1)
Total amount = Rs. 160
Now,
X + (Y/2) + (Z/4) = 160
4X +2Y +Z = 640 ---------------- (2)
Thrice as many 1 Re coins as 25 paise,
X = 3Z -------- (3)
On Solving equations 1, 2 and 3,
Z = 40
X = 3*40 = 120
Y = 220 - (120+40)= 60
50 paise's coins = 60.
Step-by-step explanation:
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