Question

A bag cost $11 more than a wallet. Each wallet cost $5. Peter brought 10 more wallets than bags. However, he paid $82 less for the wallets than for the bags. How many bags did Peter buy?

Answer 1

Given :-

• Cost of one wallet = $5
• Cost of one bag = $11 more than the cost of one wallet.
• Number of wallets he bought = 10 more than the number of bags bought.

To Find :-

• Number of bags Peter bought.

Solution :-

Given that cost of one bag is $11 more than the cost of one wallet,

⇒ 5 + 11

⇒ $16

Now, Let x be the total number of bags Peter bought. Then, number of wallets bought = x + 10. Also, total amount he paid for x bags = 16x and total amount he paid for x + 10 wallets = 5( x + 10)

According to the question,

⇒ 16x - 82 = 5( x + 10)

⇒ 16x - 82 = 5x + 50

⇒ 11x = 50 + 82

⇒ 11x = 132

⇒ x = 132/11

⇒ x = 12

Also, number of wallets bought,

⇒ x + 10

⇒ 12 + 10

⇒ 22

Hence,

• Number of bags Peter bought (x) = 12.
• Number of wallets bought (x + 10) = 22.

Answer 2

Question: A bag cost $11 more than a wallet. Each wallet cost $5. Peter brought 10 more wallets than bags. However, he paid $82 less for the wallets than for the bags. How many bags did Peter buy?

Given: Cost of wallet = $5

Amount of bag cost more than wallet = $11

Amount he paid less for wallets than bag = $82

To Find: Number of bags Peter bought.

Solution: Peter bought 12 bags.

Step by step explanation:

Cost of wallet = $5

Amount of bag cost more than wallet = $11

Amount he paid less for wallets than bag = $82

Let's say, number of bags bought by him = B

Then, wallet bought = B + 10

Cost of bag = $16B

Cost of wallet = 5(B + 10) = 5B + 50

16B - 82 = 5B + 50 ⇒ 11B = 132 ⇒ B + 12