a bag had 500 rs in the form of 1 rs, 50 paise and 25 paise coins coins in the ratio 3:8:12, find the number of each type of coins
Answers
Question :
a bag had 500 rs in the form of 1 rs, 50 paise and 25 paise coins coins in the ratio 3:8:12, find the number of each type of coins
To find :
The total number of coins in the bag
Let us assume :
According to the question
1 rs , 50 paise and 25 paise are in the ratio → 3 : 8 : 12
By taking the variable as x we get
number of 1 rs coins → 3x
number of 50 paise coins → 8x
number of 25 paise coins → 12x
Solution :
Value of 3x rs 1 coins
→ ₹ 1 × 3x
→ ₹ 3x
Value of 8x 50 paise coins
→ 8x × 50 paise
Value of 12x 25 paise coins
→ 12x × 25 paise
Total amount in the bag → ₹ 500
Value of 1 rs coins + 50 paise coins + 25 paise coins = ₹ 500
Putting the values we get,
Putting the values of x we get
No. of 1 rs coins 3x = 3 × 50 = 150 coins
No. of 50 paise coins 8x =8 × 50 = 400 coins
No. of 25 paise coins 12x = 12 × 50 = 600 coins
Total number of coins = 150 + 400 + 600 → 1150 coins
There were 1150 coins in the bag
According to the question
1 rs , 50 paise and 25 paise are in the ratio → 3 : 8 : 12
By taking the variable as x we get
number of 1 rs coins → 3x
number of 50 paise coins → 8x
number of 25 paise coins → 12x
Solution :
Value of 3x rs 1 coins
→ ₹ 1 × 3x
→ ₹ 3x
Value of 8x 50 paise coins
→ 8x × 50 paise
8x × 50/100
Value of 12x 25 paise coins
→ 12x × 25 paise
12x × 25/100
rs→3xrs
Total amount in the bag → ₹ 500
Value of 1 rs coins + 50 paise coins + 25 paise coins = ₹ 500
Putting the values we get,
3x + 4x + 3x = 500→3x+4x+3x=500
10 x = 500→10x=500
x = 500/10
x=50
Putting the values of x we get
No. of 1 rs coins 3x = 3 × 50 = 150 coins
No. of 50 paise coins 8x =8 × 50 = 400 coins
No. of 25 paise coins 12x = 12 × 50 = 600 coins
Total number of coins = 150 + 400 + 600 → 1150 coins
There are 1150 coins in the bag