Question

A bag had 500 RS in the form of 1 RS, 50 PAISE and 25 PAISE coins coins in the ratio 3:8:12, find the number of each type of coins.

PLS SOLVE! ​

Answer 1

Step-by-step explanation:

Let One rupees = 1

Let 50 paise coins = 0.5 ( 50/100)

Let 25 paise coins = 0.25 ( 25/100)

In question it is given that

Ratio of 1 rs = 3X

Ratio of 50 paise = 8X

Ratio of 25 paise = 12X

THEN EQUATION

3X × 1 + 8X × 0.5 + 12X × 0.25 = 500

3X + 4X + 3X = 500

10X = 500

X = 50

No. of one rupees coin = 3 × 50 = 150

No. of 50 paise coins = 8 × 50 = 400

No. of 25 paise coins = 12 × 50 = 600

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Answer 2

Answer:

Number of Rs. 1 coins = 150

Number of 50 paise coins = 400

Number of 25 paise coins = 600

Step-by-step explanation:

Let,

Number of Rs. 1 coins = 3x

Number of 50 paise coins = 8x

Number of 25 paise coins = 12x

★ Accoring to the Question :

Total amount = Rs. 500

⇒ 1 (3x) + 0.5 (8x) + 0.25 (12x) = 500

⇒ 3x + 4x + 3x = 500

⇒ 10x = 500

⇒ x = 500/10

⇒ x = 50

• Number of Rs. 1 coins = 3x

⇒ 3 (50)

⇒ 150

Number of Rs. 1 coins = 150

• Number of 50 paise coins = 8x

⇒ 8 (50)

⇒ 400

Number of 50 paise coins = 400

• Number of 25 paise coins = 12x

⇒ 12 (50)

⇒ 600

Number of 25 paise coins = 600

Therefore,

Number of Rs. 1 coins = 150

Number of 50 paise coins = 400

Number of 25 paise coins = 600