Question

A bag had 500 RS in the form of 1 RS, 50 PAISE and 25 PAISE coins coins in the ratio 3:8:12, find the number of each type of coins.​

Answer 1

Number of Rs. 1 coins = 150

Number of 50 paise coins = 400

Number of 25 paise coins

Step-by-step explanation:

Let,

Number of Rs. 1 coins = 3x

Number of 50 paise coins = 8x

Number of 25 paise coins = 12x

★ Accoring to the Question : Total amount = Rs. 500

→1 (3x) + 0.5 (8x) + 0.25 (12x) = 500

⇒ 3x + 4x + 3x = 500

⇒ 10x = 500

⇒ x = 500/10

⇒ x = 50

= 600

* 53%

• Number of Rs. 1 coins = 3x

3 (50)

⇒ 150

Number of Rs. 1 coins = 150

• Number of 50 paise coins = 8x

Number of 25 paise coins = 600

Therefore,

Number of Rs. 1 coins = 150

Number of 50 paise coins = 400

Number of 25 paise coins = 600

bohot mehenat lag gya XD

Answer 2

Given :-

• Denominations of coins = Rs. 1, 50 paise and 25 paise

• Ratio of the coins = 3 : 8 : 12

• Total money = Rs. 500

Let :-

• The number of Rs. 1 coin be 3x
• The number of 50 paise coins be 8x
• The number of 25 paise coins be 12x

According to the question :-

$=> 1(3x) + 0.5(8x) + 0.25(12x)= Rs. 500 \: \\ </p><p>=> 3x + 4x + 3x = Rs. 500 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: </p><p> \\ => 10x = Rs. 500 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ = > x = \frac{500}{10} = 50 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

Now :-

• No. of Rs. 1 coins = 3x = 3 x 50 = 150

• No. of 50 paise = 8x = 8 x 50 = 400

• No. of 25 paise coins = 12x = 12 x 50 = 600

I hope the answer helps you mate :)

$\huge\mathcal{\fcolorbox{lime}{black} {\orange{Be brainly ♡}}}$