Question

A bag had 6 green balls 8 rod balls one ball is drawn randomly what is the probability of getting a green ball

Answer 1

Answer:

6 greens and one randomlly draw = 7/8

Answer 2

Total number of balls in the bag = 6 + 8 = 14

No of green balls = 6

Probability of getting a green ball =

$\frac{No of green balls}{Total number of balls}$

= $\frac{6}{14}$ = 3/7

So there's a 3 in 7 chance of picking a green ball.

Hope this helps.