A bag has 3 red balls and 7 black balls one ball is taken out from bag probability of getting a red ball
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there are 10 balls in bag
red balls equals to favourable number of outcome upon total number of outcomes equals to 3 upon 10
blackball favourable number number of outcome equals to total number of outcomes equals to 7 upon a 10
red balls equals to favourable number of outcome upon total number of outcomes equals to 3 upon 10
blackball favourable number number of outcome equals to total number of outcomes equals to 7 upon a 10
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Answer:
given
total no.of red balls is=3
total no.of black balls is=7
total no of balls in bag is=10
no.of balls tore out is=1
probability to find red ball is=1-3/10
probability to find black ball is=1-7/10
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