Question

A bag has 4 red balls and 2 yellow balls. a ball is drawn from the bag without looking into the bag . what is the probability of getting a yellow ball​

Answer 1

$\huge \mathsf{\orange {\underline {\purple {\underline { Required \ answer \ ♡ \ :- }}}}}$

$\sf{Probability \ of \ an \ event  \ P(E)= \ Total \ No.of \ Outcomes \div \ No.of \ Favourable \ Outcomes}$

Here,

Favourable Outcomes = Getting a Red ball

Number of Favourable Outcomes = Number of Red Balls =4

Total Number of Outcomes =6 = Total Number of Balls

$\sf{⇒P(E)=4/6=2/3}$

Answer 2

Answer:

Probability of an event P(E)= Total No.of Outcomes÷ No.of Favourable Outcomes

Here,

Favourable Outcomes = Getting a Red ball

Number of Favourable Outcomes = Number of Red Balls =4

Total Number of Outcomes =6 = Total Number of Balls

⇒P(E)=4/6=2/3}⇒P(E)=4/6=2/3