A bag has 4 white and 3 black balls. Two balls are drawn at random. What is the probability of getting a white and a black (not necessarily in that order) with replacement?(Hint: Write your answers at least up to 2 decimal points)
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Total number of drawing 2 balls out of 10balls
=210×(10−1)=45
E= event of getting both balls of same colour
∴n(E)=24×(4−1)+23(3−1)
=6+3=9
P(E)=n(E)÷n(S)=459=51
51
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