Question

a bag has ₹420 in the denominator of ₹1, ₹2, ₹3 and ₹5 coins the no ₹1, ₹2, ₹5 coins are in the ratio of 8:1:5 how many coins of ₹5 are in the bag​

Answer 1

Answer:

please read this explanation

Step-by-step explanation:

Let the number of Rs. 1, Rs.. 2 and Rs. 5 be 8y, y, 5y.

Also, it has a total of Rs. 420

⇒ 8y + 2(y) + 5 × (5y) = 420

⇒ 8y + 2y + 25y = 420

⇒ 35y = 420

⇒ y = 12

∴ Number of coins of Rs. 5 in the bag = 5y = 60