a bag has 5 red balls and 2 yellow balls and 3 Green balls A ball is drawn at random from the bag find the probability of getting first one red ball and second one a green ball
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firstly,5+2+3=10
Probability of getting red ball=5/10=1/2
probability of getting green ball=3/10
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0
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Total no. of balls= 5+2+3=10
Probability of getting a red ball = 5/10 = 1/2
Probability of getting a green ball = 3/10
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