a bag has 6 red and 6 black balls . if a ball is taken out at random , what is the chance of getting a red ball? is it equal to the chance of getting a black ball
Answers
Answered by
26
Answer:
p(r)=6/12=1/2
Step-by-step explanation:
6 is the number of red balls and 12 is the total number of balls....
Answered by
9
Answer:
Given that
A bag contains 5 red, 6 white and 7 black balls
Total number of balls =5+6+7=18
Two balls are drawn ar random =
18
C
2
The probability that both balls are red
=
5
C
2
=
2×1×2!
5×4×3!
=10
The probability that both balls are black
=
7
C
2
=
2×1×5!
7×6×5!
=2!
The probability that both balls are red or both black =
8
C
2
10+21
=
2×1×16!
18×17×16!
31
=
153
31
P(A∪B)=
153
31
Step-by-step explanation:
change it as ur number
Hope this help you
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