Question

a bag has12 balls colored yellow, blue, green and red. The number of balls of each colour is the same. . A ball is drawn from the bag. Calculate the probability of drawing a yellow ball a greenball and a red ball​

Answer 1

Step-by-step explanation:

Total number of balls = 12

Types of balls =4(yellow, blue, green and red and)

All are of same number

therefore,

no. of yellow ball=no. of blue ball=no. of green ball=no. of red ball=12/4

=3

.: probability of drawing a yellow ball a greenball and a red ball is (3+3+3)/12

=9/12

=3/4

hope it's right

Answer 2

Step-by-step explanation:

Total number of balls = 12

It is also given that the bag contains equal number of balls of each of the four colours

(yellow, blue, green and red).

Therefore,

Number of yellow balls = Number of blue balls = Number of green balls =

Number of red balls = 3

P(yellow) = Number of yellow balls / Total number of balls = 3/12 = 1/4

P(blue) = Number of blue balls / Total number of balls = 3/12 = 1/4

P(red) =Number of red balls / Total number of balls = 3/12 = 1/4