Question

A bag-I contains four cards numbered 1, 3, 5 and 7 respectively. Another bag-II
contains here cards numbered 2, 4 and 6 respectively. A card is drawn at random
from each bag. Find the probability that the sum of two cards drawn is 9.​

Answer 1

Answer:

7+2=9 & 6+3=9

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Bag 1 = 1, 3 , 5 and 7

Bag 2 = 2, 4 , 6

For sum is 9= (3,6)(5,4)(7,2)

So required probability =

$( \frac{1}{4} \times \frac{1}{3}) + (\frac{1}{4} \times \frac{1}{3}) + (\frac{1}{4} \times \frac{1}{3} ) \\ \\ = \frac{1}{12} + \frac{1}{12} + \frac{1}{12} \\ \\ = \frac{1}{4}$

• Note probability of getting any number from bag 1 is. ( 1/4)

• probability of getting any number from bag 2 is. ( 1/3)