Math, asked by vishnu41444, 5 hours ago

A bag-I contains four cards numbered 1, 3, 5 and 7 respectively. Another bag-II contains here

Cards numbered 2, 4 and 6 respectively. A card is drawn at random from each bag. Find the

probability that the sum of two cards drawn is

i) less then 9 ii) more than a firs two digit number iii) more than equal to 7​

Answers

Answered by annasunnygeorge012
2

Answer:

          2         4         6        

3       2+3     4+3    6+3  

5       2+5     4+5    6+5

7       2+7     4+7    6+7

i) Less than 9

(2+3),(4+3),(2+5)

P(Sum less than 9) = No. of favourable outcomes / Total outcomes

                                = 3/9

                                = 1/3

                       

ii) More than the first two-digit number (Which is 10)

(6+5),(4+7),(6+7)

P(Sum more than 10) = No. of favourable outcomes /Total outcomes

                                   = 3/9

                                   = 1/3

iii) More than or equal to 7

(4+3),(6+3),(2+5),(4+5),(6+5),(2+7),(4+7),(6+7)

P(Sum more than or equal to 7) = No.of favourable outcomes/Total outcome

                                   =  8/9

                                   

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