Question

A bag is filled with of 8 Red, 7 Green, 4 Blue and 6 White coloured marbles. If a marble is picked at
random, find the probability of picking

Answer 1

Answer:

4 blue

Step-by-step explanation:

Answer 2

Answer:

balls is 1/3 or 0.3333...

Step-by-step explanation:

In a box, there are 8 red, 7 blue, 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?

In a box, there are 8 red, 7 blue, 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?

An interesting question!

ASSUMPTIONS

Other than the colours of the balls, they are identical, specifically In terms of size, weight and shape.

The one ball that is selected, is selected “sight unseen", so that its selection is truly random.

There are no balls of any colour other than red, blue and green in the box

One ball is picked randomly.

There are 8 red, 7 blue and 6 green balls in the box, a total of 21 balls altogether.

Conclusion: If a ball that is neither red nor green is picked, its colour must be blue.

We can work out the probability of selecting a blue ball in two ways:

Method 1

P(blue ball) = ( Total number of blue balls ) divided by ( Total number of balls of all colours ).

Therefore

P(blue ball) =

= ( 7 ) / ( 21 ) = ( 1/3 ) = 0.33′ = 33.3′%

Method 2

The Probability of a Red ball = ( 8/21 )

The Probability of a Green ball = ( 6/21 )

Therefore the Probability of a Red ball or a Green ball being selected is P(Red ball) + P(Green ball)

= ( 8/31 ) + (6/21) = (14/21 )

Further, the Probability that the selected ball is NEITHER RED NOR GREEN is [ 1 - the Probability that the selected ball IS RED OR GREEN) ].

THAT IS:

P(neither red nor green ball selected) =

= [ 1 - ( 14/21 )] =

= ( 7/21 ) = ( 1/3 ) = 0.33′ = 33.3′% as calculated by Method 1.

PB

In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?

In a box, there are 8 red, 7 blue and 6 green marbles. One marble is picked up randomly. What is the probability that it is neither red nor green?

A bag contains 5 red balls, 8 white balls, 4 green balls, and 7 black balls. One ball is drawn at random. What is the probability that it is black, red, or not green?

There are 3 yellow, 4 blue, 5 red, and 8 green candies, what is the probability of having neither blue nor green?

Two balls are randomly chosen from a well shake box with seven red balls and 3 green balls. What is the probability that both the balls are red?

In this, they ask the probability of finding blue ball, Here the events are mutually exclusive events, i.e. one event does not influence other event, to be more clear, selection of green ball, does not affects the no. of red and blue balls.

So, here P(neither red nor green) implies nothing but P(blue balls)

Let n(B) be no. of blue balls, so n(B)=7

Also, n(S)=n(R)+n(B)+n(G)=8+7+6=21 where n(R),n(B),n(G) are no. of red, blue, green balls respectively.

Then P(B)=n(B)/n(S)

P(B)=721

P(B)=13

i.e. probability of getting neither red or green balls is 13 or 0.3333...